You could probably overload '.' to mean '->', but '->' is not overloadable. Watch out for interaction with '.='. You may not be able to pass arguments to your methods, since '.' only takes two arguments.

Why do this? I don't much approve of the purging of C notation from perl 6, and there seems to be no reason at all for it to spill back into perl 5.

After Compline,
Zaxo

In reply to Re: Overloading operators: -> to . by Zaxo
in thread Overloading operators: -> to . by theAcolyte

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