You don't need the exists keyword either, the following symetric code should work just fine -

# define your hash entry
$foo{bar} = sub { print "Hello Perl!\n" };

# note the use of && operator, which will short-circuit
# if $foo{bar} is undef.
$foo{bar} && $foo{bar}();

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In reply to Re: Shortening "$bar{foo} if exists $bar{foo}"? by Roger
in thread Shortening "$bar{foo} if exists $bar{foo}"? by BUU

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