Small bug:

#!/usr/bin/perl -wl

$s = "this is an\b\b not correct usage";
$s =~ s[.\cH][]g;

print $s;

print "and one's still there" if grep { ord == ord"\b" } split //,$s;
__END__
output:
this is  not correct usage
and one's still there

[download]

It looks correct at first glance, but the second backspace is still there.

Update: Much better. Only problem is in the case of a leading \b, you can get into an infinite loop. However only the regex needs alteration.

$s =~ s/(?:[^\cH]\cH|^\cH+)//g while ...

[download]

antirice    
The first rule of Perl club is - use Perl
The ith rule of Perl club is - follow rule i - 1 for i > 1

In reply to Re: Re: should this backspace removal code be done better? by antirice
in thread should this backspace removal code be done better? by smackdab

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