I am a perl newbie. I wanted to confirm few things based on your answer. Here are my questions

1. The operation ($!+0) causes $! to be evaluated in numeric context because of the binary + operator. The parenthesis around $!+0 are necessary here because of the preceeding concatenation operator which is left associative and has the same precedence as that of binary + operator. Now, once $!+0 is evaluated in numeric context, to say number 2, does it again get evaluated in string context by the preceeding concatenation operator to string of one character i.e. "2" ?

2. Within a string, say "Hello World!", the default context is string context. So if I have, 

@array = (perl, monks);
print "Hello @array World!";

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@array is evaluated in string context inside "Hello @array World!" so as to yield a single string "perl monks" which is then interpolated into "Hello World!" so as to give "Hello perl monks World!".
Is this observation true? and is this what you are refering to as the "flattaned list" the join operator accepts ?

3. Why does 
print @array;

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prints: perlmonks
instead of: perl monks ?

4. What are all the contexts (like numeric context, string context) that exist which are variations of scalar context or list context?

In reply to Re: string context and list operators (was Re: Array in scalar context.) by Anonymous Monk
in thread Array in scalar context. by the_0ne

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