This won't work, because it returns the current date. First, there's a typo in my post. The example should read: 



/export/home/mars-stats/device/config/2000/0825/blah/blah/blah.txt
Your code would return: 

"blah-Sun_Aug_27_03:18:29_2000.txt"
Which is a problem, if I want to run the program on a month old file, and create a file with THAT date on it. So, my new brilliant (?) idea is the following: Since each day, a new directory is created which contains the files I need to process, read the path to the file that I want to process: 

#get current working directory; let's say it returns:

$path = "/export/home/mars-stats/device/config/2000/0825/blah/blah/blah.txt"
Then create the rule: 


if while reading $path, you  encounter:

begins with "/", followed by 1 or more "/", then one or more word characters, then a "1" or 
a "2" followed by more than one digit, followed by one or more word characters
until the end of the line, grab the string between the first word 
character preceding a digit and the next word character,and replace the "/" with "."
this should return "2000.0825" which I could use to append to my new file. This rule, if I can figure out the syntax, would cover any input file created in between the years 1900 - 2999. Not bad mileage! Am I missing something here? Be gentle; this is the first program I've ever written in ANY language!

In reply to Re: Parsing File Timestamp? by Limo
in thread Parsing File Timestamp? by Limo

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