There is a slick touch of confusion happening that's worthy of an obfu. 

$ perl -e'($alpha, $delta) = qw{A D};$test = q($delta and $alpha); pri
+nt eval $test'
A$

[download]
$delta and $alpha are substituted all right, but the and operator gets evaluated, too. 'D' is true, so 'A' is evaluated and becomes the value of the expression.

I don't know of a way to get double interpolation that will survive this problem.

Update: Well, there is a way of course, but it's really crude, $test =~ s/\$(\w+}\b/$$1/g;

After Compline,
Zaxo

In reply to Re: Resolving scalars in a scalar by Zaxo
in thread Resolving scalars in a scalar by Anonymous Monk

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