qw is short for quoted words. It builds a list. So the code ($alpha,$delta)=qw/A D/; means: build a list with two elements A and D, and assign value A to $alpha, and value D to $delta.

In your example, $test=q{qq{$delta and $alpha}}; is equivalent to $test='"$delta and $alpha"'. Which means: give me a variable $test, and make the value equal to "$delta and $alpha" (with double quotes). When you evaluate this expression -
print eval ' "$delta and $alpha" ';
it is equivalent to the code -
print "$delta and $alpha";
Which will print "D and A" natually.

eval evaluates the value held inside the string given, "$delta and $alpha", in this case, which returns a scalar string.

In Zaxo's example, he was doing -
print eval '$delta and $alpha';
which is equivalent to -
print $delta and $alpha;
which will print the value of $alpha. Note that in the second case, there is no double quote in the equivalent code.


In reply to Re: Re: Re: Re: Re: Resolving scalars in a scalar by Roger
in thread Resolving scalars in a scalar by Anonymous Monk

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