Using Perl::Expect to match a regex. But it isn't when it should!.

Run Perl::Expect in debug and internal mode - output below. Where it shows what it is trying to match and the regex it is using.

Matches OK when using a script to match the string and the same regex.

I have tried $Expect::Multiline_Matching = 0 and = 1 for the same effect. 

spawn id(4): Does ` #00 LOGGED IN NORTEL1 12:02   3/11/2003 \r\n\r\012
+>logo\r\r\012TTY #00 LOGGED OUT NORTEL1 12:02   3/11/2003 \r\012SESSI
+ON DURATION:  00:00 \r\012\r\012>'
match:
  pattern #1: -re `LOGGED OUT.*TTY'? No.
  pattern #2: -re `LOGGED OUT.*>'? No.

[download]
This is the code from the Expect.PM re multiline matching. 
 } elsif ($pattern->[1] eq '-re') {
            # m// in array context promises to return an empty list
            # but doesn't if the pattern doesn't contain brackets (),
            # so we kludge around by adding an empty bracket
            # at the end.

            if ($Expect::Multiline_Matching) {
              @matchlist = (${*$exp}{exp_Accum}
                            =~ m/$pattern->[2]()/m);
              ($match, $before, $after) = ($&, $`, $');
            } else {
              @matchlist = (${*$exp}{exp_Accum}
                            =~ m/$pattern->[2]()/);
              ($match, $before, $after) = ($&, $`, $');
            }

[download]
Any pointers as to why this isn't working? Update:- Simplifying this problem out of Expect:- Why does the following not match:- 
#!/usr/bin/perl -w
use strict;
use warnings;
use diagnostics;

my $String = "` #00 LOGGED IN NORTEL1 12:02   3/11/2003 \r\n\r\012>log
+o\r\r\012TTY #00 LOGGED OUT NORTEL1 12:02   3/11/2003 \r\012SESSION D
+URATION:  00:00 \r\012\r\012>";
my  @matchlist = ($String =~ m/(.*LOGGED OUT.*>)/m);
print @matchlist;

[download]
Nothing returned

20031103 Edit by jeffa: Changed title from 'Perl::Expect - Regular Expression not matching ', added strikes

In reply to Expect.pm - Regular Expression not matching by set_uk

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