Ummm, I have no problem doing the substitution using the code supplied:

$line = "She was very absorbed in her homework.";
$word = "absorb";

print STDOUT "Line: $line\n";
$line =~ s/($word(?:s|ed))/<b>$1<\/b>/igm;
print STDOUT "New Line: $line\n";
print STDOUT "\$1 contains: $1\n";

[download]

Of course, I might consider changing it slightly to read:

$line =~ s/\b(${word}(?:s|ed)?)\b/<b>$1<\/b>/igm;

[download]

However, I did just discover that there is something more going on here, because while the original (without the \b) does set something in $1, my change doesn't (despite doing the substitution properly).

And finally, if you're just doing a match why are you using s///?

In reply to Re: Re: Re: quick question about parenthesis and regular expressions by jreades
in thread quick question about parenthesis and regular expressions by cranberry13

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