This is how I try to remember this.  push takes a list as argument and hence  $_ cannot be taken as a default argument for this.

Update But then as Smylers pointed out  print also takes a list of arguments but still takes $_ as default argument when there is none. puzzling ??

-T

use perl; use strict;

In reply to Re: Re: •Re: perl 1-liner to join a list? by thens
in thread perl 1-liner to join a list? by bfdi533

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