Background
I have a csv file and i am reading this file in using split.something like this:
while (<>) {
@array = split(/,/, $line);
}

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Now the problem is that one of my csv record contains a "," in the record itself. this is confusing the split int breaking the line in the wrong place.
data looks like :
121212, "Simpson, Bart", springfield

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I am trying to get it to look like:
121212, Simpson Bart, springfield

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Notice Bart Simpson is quoted in the original, that is a function of MS Excel. it adds quotes around any data that is being exported to csv and contains a comma in the data.
I really can't use modules like :Text::CSV or DBI::CSV. As a mater of fact i can't use any modules. Thus i am trying to use regular expressions.
All i need to do is take out the extra "," comma that is appearing in the the field

Again, I already know that i can do this with some modules but i dont have root to the machine right now and it is not possible for me to install any new modules. I am trying to do this by using reqular expressions. Here is what i have so far.

open (SYST, "$upload_dir/$filename");
while (defined ($line = <SYST>)) {
        next if ($line =~ /^\s+/) ;

        if ($line =~ /"(.*)"/) {
                print "found line= $line\n";
                $line =~ s!
                                "(.*)"
                        !
                                (s/,/sprintf("_", $&))
                        !ee;
                print "now line= $line\n";
        }
}
close (SYST);

[download]

Here i am searhing if a line contains a "(.*)" (something with quotes around it.
then i am run a sub expression on it that will take what ever is in $1 and run a replace on one character (,) only.
My regular expresion skills are not high and what you see above only needs a slight tweak from what i can tell.
I need to know i can make the secord half work!

Here is a example of what i am trying to do:

line = 121212, "Simpson, Bart", Springfield<br>

if ($line = /"(.*)"/) {
$1 = "Simpson, Bart"; Now contains

# now run replace on Simpson, Bart
$1 =~ s/,/_/g;

$1 = "Simpson_ Bart"; # Now contains

now put everyting back together.

121212, Simpson_ Bart, Sprigfield
}

[download]

Thanks in advance!

In reply to regular expression (search and destroy) by data67

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