But how do I find out if a word is not on a line
Just use the negated version of the regex match e.g
shell> perl -le 'print "yep" if "foo bar" !~ /baz/' yep
The second thing i would like to know is how do I remove the first char from a string in an array element?
Using substr is a pretty sensible approach e.g
shell> perl -le '$_="xfoo"; print; substr($_,0,1)=""; print' xfoo foo
Or you could use a simple s/// e.g
shell> perl -le '$_="xfoo"; print; s/^.//; print' xfoo foo
The third thing is i want to remove all chars up to the last ',' in an array element.
You could use a naive regex for this which would just match a comma and then everything that wasn't a comma to the end of the string
shell> perl -le '$_="foo,bar,baz"; print; s/,[^,]+$//; print' foo,bar,baz foo,bar
But if you're parsing comma-delimited fields then the likes of Text::xSV is a much saner approach.

The above answers can be applied to an array element just as easily a simple scalar variable as they're both scalar values.

HTH

_________
broquaint


In reply to Re: Not find a word / remove first char in string / remove last value in list by broquaint
in thread Not find a word / remove first char in string / remove last value in list by Anonymous Monk

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