While significantly faster than the OP's, I believe it suffers from some of the same scalability issues. That's one thing I hate about regular expressions: determining the complexity of an algorithm built on them tends to be very difficult.

Anyway, that also suffers from another problem. Try it with 

my @a = ('a' . 'X' x 32768, 'a' . 'O' x 32768);

[download]
and you'll get an error: 
Quantifier in {,} bigger than 32766 in regex; marked by <-- HERE in m/
+(.{ <-- HERE 32767}).*\0.*\1/

[download]

-sauoq
"My two cents aren't worth a dime.";

In reply to Re: Re: finding longest common substring by sauoq
in thread finding longest common substring by revdiablo

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