Except that the parens () will be used for grouping and capturing by the regex, and so won't match the literals in the string; 

perl -e '$s = q|b(s)|; print  "without quotemeta" if $s =~ /$s/; print
+ "with quotemeta" if $s =~ /\Q$s\E/;'

with quotemeta

[download]

qq

In reply to Re: Re: Re: Matching brackets in Regular Expression by qq
in thread Matching brackets in Regular Expression by Levan

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