Ooh, that's weird. The problem is clearly with precedence and context.

$ perl -e'print for (1..10 or a..z);'
abcdefghijklmnopqrstuvwxyz$

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I have no idea why that doesn't mean print for 1..10;. I can make a case for that meaning print for 10;, but it is crazy that 1..10 evaluates false on the left of low precedence or.

I'm eagerly anticipating an explanation.

Update: This prints nothing, 

$ perl -e'print scalar(1..10)'
$

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This must be hooked up with the odd special case mentioned by davido that $. is hooked up with flipflops when thay have constant arguments. Dwimmerie gone berserk.

After Compline,
Zaxo

In reply to Re: for loops and 'and' by Zaxo
in thread for loops and 'and' by Anonymous Monk

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