Ok, here's my attempt after Anonymous monk's intention is clear.

$string =~ m/(?:(?=.*?X)X|(?!.*?X))(\S+)/;

[download]
And here's a little test -

$string1="abcX123";
$string2="abc123";

$string1 =~ m/(?:(?=.*?X)X|(?!.*?X))(\S+)/;
print "$1\n";

$string2 =~ m/(?:(?=.*?X)X|(?!.*?X))(\S+)/;
print "$1\n";

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And the output is as expected, and both in $1 -
123
abc123

[download]
And the tricky bit in the above regex is the (?:(?=.*?X)X|(?!.*?X)) part, which defines an optional anchor point.


Update: I hit my head on the wall a couple of times, literally, after I saw sauoq's much clever solution below. I was locked up with the idea of an optional anchor point, that I have failed to notice the vital bit of the clue - capture till the end, that defined a fixed anchor point to look back from, instead of a floating anchor point that looks forward. Although my solution worked, it was way too complicated than is necessary.

An important lesson I have learnt today: when a problem seems rather complicated, take a step back and look for other clues. The alternative solution is probably staring right in my face!

In reply to Re: Re: Capturing everything after an optional character in a regex? by Roger
in thread Capturing everything after an optional character in a regex? by Anonymous Monk

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