I have some code in a file which I am loading with do. It's a mixture of code to run and subroutine definitions. I'm loading this file multiple times with different package statements in effect to declare the subs in different packages.

In some debugging messages I'm trying to use __PACKAGE__ to give the current package, but it isn't working. It's always printing 'main', even though subs are ending up in the correct package. Attached below is an example case.

Can anyone figure out what I'm missing?

#### test1-do.pl
$var++;

print "  Point A: " . __PACKAGE__ . " $var\n";
#### test.pl
#!/usr/bin/perl -w

$main::var = $B::var = 5;

print "Point 1: " . __PACKAGE__ . " $main::var $B::var\n";

package B;
$rv = do "test1-do.pl";
die $@ if $@;
die $! unless defined $rv;

print "Point 2: " . __PACKAGE__ . " $main::var $B::var\n";

__END__
As I understand it the code in the do should be evaluated in the same 
+package it was called from.
This does happen for the assignment ($var++), but it doesn't seem to g
+et the right __PACKAGE__

#### Actual output
Point 1: main 5 5
  Point A: main 6
Point 2: B 5 6
             ^^ $B::var has actually been changed

#### Expected:
Point 1: main 5 5
  Point A: B 6
Point 2: B 5 6

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--
integral

In reply to 'package' and 'do' by integral

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