Dear Almighty Perl Mongers,

My thought was to convert this mess to a regex substitution. 

$bday = "8/16/97";
$firstname = "Benjamin";
$lastname = "Biederman";

@DOB = split /\//, $bday;
@month = split //, $DOB[0];
@day = split //, $DOB[1];
$digits_month = @month;
$digits_day = @day;
$temp_month = $DOB[0];
$temp_day = $DOB[1];
if ($digits_month==1) {
    $bday = "0";
    $bday .= $temp_month;
} else {
     $bday = $temp_month;
}
if ($digits_day==1) {
    $bday .= "0";
    $bday .= $temp_day;
} else {
    $bday .= $temp_day;
}
    
@new_username_a = split //, $firstname;
@new_username_b = split //, $lastname;
$login_name = lc $new_username_a[0];
$login_name .= lc $new_username_b[0];
$login_name .= $bday;

[download]
to something like --- 
$login_name = "$firstname $lastname $bday";
$login_name = s/^(^\C)\s(^\C)\s(^\d{1,2})\/(\d{1,2})\/(\d{1,2})/$1$2$3
+$4/;  
#notice that to 2 digit bit is not reflected by this regex

[download]
Thanks,
Chris

janitored by ybiC: Balanced <code> tags around code only, retitle from " REGEX optimization" for better searching

In reply to Convert split to regex by 3dbc

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