Hi,Monks?!!!!
This code will bring back information from a database, and variable $line
will bring sometimes more than one result. How can I print this variable out side of
the while loop and print all the results coming back from the database.
How can I do that?
If I print variable $line out side of the while loop it will only print
the first result I know that is because there is no interaction on the variable to print all
the results found, somehow I know that there is a way to assign the results into an array
and dynamically out side be able to print everything found, I just can't remember how it is done
I thank you very much for this help!!!



    $sth = $dbh->prepare($sql);
    $sth->execute() || die $sth->errstr;


    while ($pointer = $sth->fetchrow_hashref)
    
    {

              
       $line=$pointer->{'LINE'};
       $ins =$pointer->{'INS#'};
       $number =$pointer->{'NUMBER#'};

        if($line_type)
        {        
           $ result = "<td><a href=found.html?line=$line>Found $line</
+td><br>";
           exit;
        }
        else
        {
           print "<META HTTP-EQUIV=\"refresh\" CONTENT=\"0; URL=notfou
+nd.html\"> \n";
           exit;
        }
      
     }
      
}

print $line;

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In reply to While Loop Problem! by Anonymous Monk

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