No, it doesn't.

By removing use threads, you are basically disabling shared variables, making the process of sharing a variable a noop.

What you have without use threads is a very expensive, object oriented way of pushing and popping an array in a single process.

Liz

In reply to Re: Re: Re: Placing references onto thread queues (Perl 5.8) by liz
in thread Placing references onto thread queues (Perl 5.8) by fx

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