Brilliant! This works fine.

I am curious to know how this statement works:

$data[$i] =~ s#^(\d{16})#$_ = $1; tr/0-9/A-J/; $_#e

I understand some pieces of it:
-> the s is for substitution; ^d16 is for first 16digits;
-> tr does the conversion. # delimits;

Can you please let me know, how the whole piece fits in to do the substitution.

thanks

In reply to Re: Re: Re: Re: Simple Encryption question by rman
in thread Simple Encryption question by rman

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