By your reasoning, the following code should work, and any code in the mutator to prevent it disqualifies the method as a mutator

That's correct. Accessors/mutators, by definition, provide direct access to the underlieing attributes. Since Perl is a dynamically typed language, that means doing any sort of validation on the data makes it something other than an accessor/mutator. If you're in a statically typed language, then the language does some validation for you, and it would thus still be an accessor/mutator. The important point is that you're not doing validation in your own code.

So what if it isn't an accessor/mutator? More often than not, that's a good thing. That isn't to say you have a well-designed object, but you're closer to it than if you provide direct access.

----
I wanted to explore how Perl's closures can be manipulated, and ended up creating an object system by accident.
-- Schemer

: () { :|:& };:

Note: All code is untested, unless otherwise stated

In reply to Re^5: OO Getters/Setters by hardburn
in thread OO Getters/Setters by theAcolyte

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