Thank you, Abigail. Can you please explain how does the replacement part of your expression work? If I understand correctly, /e evaluates $1 || "$2 " -- that way if $1 is not empty, it should not add second part?

--dda

P.S. I added end-of-line processings as was suggested by aragorn: 
s/(\d[,.]\d)|([^\w\s](?!\s)(?!$))/$1 || "$2 "/ge;

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In reply to Re: Re: Regex to add space after punctuation sign by dda
in thread Regex to add space after punctuation sign by dda

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