Evaluating $1 || "$2 " means you get $1 if $1 is true (which means, anytime \d[.,]\d matches), otherwise you get $2 (the punctation character), followed by a space.

I would handle end-of-line processing as follows: 

s/(\d[,.]\d)|([^\w\s])(?=\S)/$1 || "$2 "/ge;

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A single positive look-ahead is, IMO, more clear than two negative look-aheads.

Abigail

In reply to Re: Regex to add space after punctuation sign by Abigail-II
in thread Regex to add space after punctuation sign by dda

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