Actually, the odd operator is
=, not
+=. Most operators will dictate the
context of their operands, and so does
+=:
both operands are in scalar context. But
=
is special cased, there the operands could be either
in list or scalar context - and it's the left operand
that decides.
The following program might be of interest:
#!/usr/bin/perl
use strict;
use warnings;
my ($a, @a) = ("");
sub foo : lvalue {
print wantarray ? "LIST: " : "SCALAR: ";
wantarray ? @a : $a
}
foo () = 1; print "\$a = $a; \@a = [@a]\n";
(foo ()) = 2; print "\$a = $a; \@a = [@a]\n";
foo () += 3; print "\$a = $a; \@a = [@a]\n";
(foo ()) += 4; print "\$a = $a; \@a = [@a]\n";
__END__
SCALAR: $a = 1; @a = []
LIST: $a = 1; @a = [2]
SCALAR: $a = 4; @a = [2]
SCALAR: $a = 8; @a = [2]
Abigail
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