my @a = ([  1,  8],
         [  9, 11],
         [ 20,  2],
         [ 22,  9],
         [ 31,  7],
         [ 38,  8],
         [ 46,  8],
         [ 54,  8],
         [ 62, 30],
         [ 92, 12],
         [104, 30]);

[download]
Or if your array is large, and you want to save memory: 
my @b = (
    [1,  9, 20, 22, 31, 38, 46, 54, 62, 92, 104],
    [8, 11,  2,  8,  7,  8,  8,  8, 30, 12,  30]
);

[download]
But if you look carefully, the "keys" aren't necessary at all - if all you do is process the data in order, the keys can be calculated from the values, and all you need to keep is: 
my @c = (8, 11,  2,  8,  7,  8,  8,  8, 30, 12,  30);

[download]

Abigail

In reply to Re: Managing Client Specific Hashes by Abigail-II
in thread Managing Client Specific Hashes by Grygonos

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