Let's see if I did my homework right.

An "/e" will cause the replacement portion to be treated as a full-fledge Perl expression and evaluated right then and there.

An "||" Logical "OR" if the left expression true, then right is never evaluated.

I think I got a handle on it now. Thanks for the pointers and making me do the homework ;-)

In reply to Re: Re: Regular expression question by TASdvlper
in thread Regular expression question by TASdvlper

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