Check out this experiment: 

$ cat argvtest.pl
printf "I saw %d arguments\n",$#ARGV+1; #show how many
@argsin=@ARGV; # Snarf in the argnuments
 
printf "They were \"%s\"\n",join(",",@argsin); # and what

[download]
a test run shows: 
$ perl argvtest.pl 1 2 3 4
I saw 4 arguments

They were "1,2,3,4"

[download]
 $#ARGV is the argument count minus one or in other words the last index of the array @ARGV or the list of arguments passed to the script.

With that in mind your test should look something like: 

if ( $#ARGV < 0 ) { # NOTE: not != 0 
    printf "I expected an argument not simple refutation\n";
    exit(0);
}

[download]

UPDATE: Re-reading your original post I picked up on something...

You tried: 

@RecievedArray=$ARGV[0];

[download]
Since @ARGV is an array of scalars you are just referencing the first element of @ARGV which is itself a scalar and attempting to assign that to an array.

I set up another experiment just to demonstrate what is going on: 

use Data::Dumper;
 
@ry=qw/ a b c d /;
@ry2=$ry[0];
 
printf "First array:\n";
print Dumper(\@ry);
 
printf "Second array:\n";
print Dumper(\@ry2);

[download]
When that code is run you get the following: 
First array:
$VAR1 = [
          'a',
          'b',
          'c',
          'd'
        ];
Second array:
$VAR1 = [
          'a'
        ];

[download]
As you can see all that gets assigned to the second array is the first element of the first array.

Hope all this helps.

Peter L. Berghold -- Unix Professional
Peter at Berghold dot Net
   Dog trainer, dog agility exhibitor, brewer of fine Belgian style ales. Happiness is a warm, tired, contented dog curled up at your side and a good Belgian ale in your chalice.

In reply to Re: Passing arguments by blue_cowdawg
in thread Passing arguments by Anonymous Monk

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