Yep. At first blush if you use $0 that will give you the name of the script being executed. But be careful. Let me show you a few case studies.

Invoking a script via the interpreter

Consider the following very simple script: 
#!/usr/bin/perl -w 
print $0,"\n";

[download]
If I invoke it as 

perl testzero.pl

[download]
sure enough it prints testzero.pl to stdout. Let's add a wrinkle! If I execute it as perl /home/peter/testzero.pl then then entire path name will be printed to stdout.

chmod'ed script

If I do a chmod 755 testzero.pl on my hapless script (assuming *nix environment here) then I have a similar problem. Executing 

./testzero.pl

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will yield ./testzero.pl to stdout and so forth.

In summary, hes you can get the path name of the script being executed but make sure you understand all of the implications.

Peter L. Berghold -- Unix Professional
Peter at Berghold dot Net
   Dog trainer, dog agility exhibitor, brewer of fine Belgian style ales. Happiness is a warm, tired, contented dog curled up at your side and a good Belgian ale in your chalice.

In reply to Re: Get My Own Name by blue_cowdawg
in thread Get My Own Name by peschkaj

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