This is an odd case to use a regex for, actually (it kind of demonstrates a lack of understanding of what a regex is good for).

That being said, though, this: 

/(?=.*a)(?=.*e)(?=.*i)(?=.*o)(?=.*u)/i

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should do you pretty easily. Granted, it makes use of positive look-ahead which isn't strictly speaking "regular". The basic description of the regex is: there exists a place in the string (the beginning of the string, for example), after which exists an "a" AND after which exists an "e", etc.

To do this with a true regular expression (and hence without lookahead assertions), you'd want to do it by essentially creating a list of all 5-factorial permutations of aeiou, and, over these permutations like so (written out kind of long-hand so that the idea should be transparent): 

my @regex_pieces = ();
foreach my $permutation (@permutations) {
    my @vowels = split //, $permutation;
    push @regex_pieces, join(".*", @vowels); 
}
my $regex = qr/@{[join("|", @regex_pieces)]}/i;

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:Wq
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In reply to Re: regex testing for ALL of the vowels in a scalar by etcshadow
in thread regex testing for ALL of the vowels in a scalar by D'Oh!!

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