Not to be a stickler, but it's not exponential growth. It's worse than that. For instance, 2**4 = 16, but 4! = 24. Choose any base j, and there's a number n such that j**n < n!. Of course, this only strenghens your point...:).

thor

In reply to Re: Re: Operator for "these expressions, in any order" by thor
in thread Operator for "these expressions, in any order" by jsalvata

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