hello monks!
I was inteded to compare two hash and I fall in this:
%aa=(uno=>1, due=>2);
%bb=(due=>2, uno=>1);
  if (%aa eq %bb){print "equal\n"}
  else {print "boh?\n"}

__END__
:>equal


###########################
%aa=(uno=>1, due=>2);
%bb=(due=>2, uno=>1111111322321111111111);
  if (%aa eq %bb){print "equal\n"}
  else {print "boh?\n"}

__END__
:>equal

[download]

Why ? there is some smart way to compare two hash without foreach sort keys ??
%aa eq %bb seems to compare only the keys..

TIMT1WToLooseReputation
greetings from sunny roma
lor*

20040220 Edit by BazB: Changed title from '%a eq %b'

In reply to Comparing hashes without sorting the keys by Discipulus

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