Greetings, monks.

As several monks have kindly pointed out my question about sed was not clear, therefore I revise it here. Even though it is a very simple problem, bear in mind that

I am very new and clueless

and

I've benefited a great deal from the simple suggestions made to me thus far.

I want to be able to use perl interactively with vi to achieve the following. If the file has this:


Line1
Line2
Line3
Line ‘1’
Line ‘2’
Line ‘3’
Line4
Line5

[download]

I want it to ultimately look like this:


Line1
Line2
Line3
NewLine1
(+3) Line ’3’;fac=3
(+2) Line ‘2’;fac=2
(+1) Line ‘1’;fac=1
Line4
Line5
MeanLine

[download]

So far, I can get this if the file is already in the Order of the second file—what I want it to do is flip those 3 lines before applying the other changes. The script I have right now looks like this:


#!/usr/bin/perl -w

while (<>) {
    if (/'3'/) {
        s/^L/(+3) L/g;
        s/'3'/'3';fac=3/g;
        s/^/Newline1\n/g
        } 
     
    if (/'2'/) {
        s/^L/(+2) L/g;
        s/'2'/'2';fac=2/g;
        } 
    if (/'1'/) {
        s/^L/(+1) L/g;
        s/'1'/'1';fac=1/g;
        } 
    if (/Line5/) {
        s/Line5/Line5\nMeanLine/g
        }
    print "$_";
    }

[download]

I had a sed script that would reverse the order of the lines based on their matching a pattern-- what I'm trying to find is a Simple way to achieve this same result. While substitution looks pretty much the same as sed in perl, I can't seem to find anything like sed's ability to put stuff in a hold space and retrieve it later, like this sed does:

/'1'/{
h     
d     
}     
/'2'/G
/'2'/{
h     
d     
}     
/'3'/G
/'3'/{
h     
d     
}

[download]

Putting this through s2p gave me 3 pages of code I won't understand until saint level.

I'm also trying to get it to do what the program above does-- work over a block of text in a file being edited with vi editor, and invoked thus:

:1,17! perlprogram

Thanks in advance for your help.

In reply to sed to perl conversion revisted by NovMonk

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