Here is a regex solution to you problem: 
while (<DATA>) {
   chomp;
   print "$_ has no bar\n" if /^([^b]|b[^a]|ba[^r])+$/;
}

__DATA__
bar
foo
"bar" blah
baz "bar" blah
"test" blah
"test2"

[download]

-Mark

In reply to Re: positive regex for inverted match by kvale
in thread positive regex for inverted match by kgimpel

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