neniro,
I do not believe this accomplishes what doran was after. Instead of finding the 3 highest values of the inner hashes, you are finding the highest value in each inner hash. I think the way to go is to sort all the second level hash values into an array and pick the top 3. 
my @vals = sort {$b <=> $a } map { values %{$hoh->{$_}} } keys %$hoh;
my ($one, $two, $three) = @vals[0..2];

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Cheers - L~R

Update Completely missed that tinita had an almost identical solution below. In the case of a very large HoH, you can avoid sorting and gain a bit of efficiency with the following: 

my @top_3;
my $filled = 0;
VAL:
for my $val ( map { values %{$hoh->{$_}} } keys %$hoh ) {
    if ( ! $filled ) {
        for ( 0 .. 2 ) {
            if ( ! defined $top_3[$_] ) {
                $top_3[$_] = $val;
                $filled = 1 if $_ == 2;
                next VAL;
            }
        }
    }
    if ( $val > $top_3[0] ) {
        ($top_3[0], $top_3[1]) = ($val, $top_3[0]);
    }
    elsif ( $val > $top_3[1] ) {
        ($top_3[1], $top_3[2]) = ($val, $top_3[1]);        
    }
    elsif ( $val > $top_3[2] ) {
        $top_3[2] = $val;
    }
}
print "$_\n" for @top_3;

[download]

In reply to Re: Re: Sorting values of nested hash refs by Limbic~Region
in thread Sorting values of nested hash refs by doran

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