This appears to be a C solution...and an incorrect one at that. 
/* == is yr a leap year == */

int IsLeapYear(int Year)
/* Return SUCCESS if Year is a leap year,
 FAIL otherwise */
{
  if ((Year % 4 == 0) && (Year % 4000 != 0) &&
      ((Year % 100 != 0) || (Year % 400 == 0)))
    return(SUCCESS);
  return(FAIL);
}

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Originally posted as a Categorized Answer.

In reply to Re: Leap Year by Anonymous Monk
in thread How do I determine if a given year is a leap year? by Adam

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