Hi Monks,

still "only" a regexp question:

I have 

$a='abab';
$b='a(.)';
$c='a$1';

print "\$a $a\n";
print "\$b $b\n";
print "\$c $c\n";

$a =~ s/$b/$c/g ;    # so this is  s/a(.)/a$1/g

print "\$a $a\n";

[download]
which prints 
$a abab
$b a(.)
$c a$1
$a a$1a$1

[download]
What I wanted/expected was the last line to be 
$a abab

[download]
It's clear, after $c is evaluated to a$1 $1 isn't further evaluated to the content of the matching braces in the regexp.

How to change the above code so that the output is my expected one? Is it possible to combine this two different evaluations? Thanks for any help.

regards,
almaric

In reply to regexp $1 in a variable by almaric

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