Regexes work on scalars (individual variables), not on whole arrays at a time.
However, perl comes to the rescue with it's built-in grep function
#! perl -slw use strict; my @text = ( "Hi there 11", "Fred blamed me", "17 o clock", "It's snowing hampsters", "Pickles are people too!" ); if ( grep( /11/, @text ) || grep( /are/, @text ) ) { print "test successfull"; } else { print "We messed something up again"; }; __END__ P:\test>334482 test successfull
This asks grep to scan each element in the array and pass through only those that match the regex.
However, in a scalar context, it returns not the elements themselves, but a count of those that matched. If the number matched is non-zero, then the if statement will be true.
Once you've got that working, you will see that there is no need to scan the whole array twice, as you can put both regexes into the same grep and look for them both in one pass.
if ( grep( /11/ || /are/, @text ) ) { print "test successfull"; } else { print "We messed something up again"; };
In this case, it is also possible to remove the need to match against each string twice, by combining the search terms into a single regex.
if ( grep( /(11|are)/, @text ) ) { print "test successfull"; } else { print "We messed something up again"; };
In reply to Re: Matching arrays?
by BrowserUk
in thread Matching arrays?
by Anonymous Monk
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