Obviously, I can't do $p->$key==$val, much as that would come in handy right now. 
$ perl -le 'sub a { "x" } sub b { "y" }; $p = bless {}; for $key ( qw(
+ a b ) ) { print $p->$key() }'
x
y

[download]

Yes, you obviously can't do that.

In reply to Re: $var as accessor name? by Fletch
in thread $var as accessor name? by matija

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