#!/usr/local/bin/perl -sl use strict; use warnings; local $, = ' '; { no strict 'refs'; no warnings 'uninitialized'; my $C = 0; sub query{ my $i = shift; my $x = ${"a_$i"}; return (0 <= $x and $x < $C and ${"b_$x"} == $i ) ? 1 : 0; } sub insert{ my $i = shift; if( !query( $i ) ) { ${"b_$C"} = $i; ${"a_$i"} = $C; $C++ } } sub del{ my $i = shift; if( query( $i ) ) { $C--; my $x = ${"a_$i"}; my $y = ${"b_$C"}; ${"b_$x"} = $y; ${"a_$y"} = $x; } } sub clear{ $C = 0; } } my @numbers = map{ int rand( 2**16 ) } 1 .. 10; print 'Query before insert'; printf "%5d : %s\n", $_, query( $_ ) for @numbers; insert $_ for @numbers; print "\nQuery after insert"; printf "%5d : %s\n", $_, query( $_ ) for @numbers; del $_ for @numbers[ 0..4 ]; ## Delete half print "\nQuery after deleting half"; printf "%5d : %s\n", $_, query( $_ ) for @numbers; del $_ for @numbers; ## Delete them all regardless if they still exist +s print "\nQuery after deleting the rest"; printf "%5d : %s\n", $_, query( $_ ) for @numbers; -------- Query before insert 56155 : 0 20459 : 0 15365 : 0 55048 : 0 47183 : 0 49635 : 0 32939 : 0 17320 : 0 54582 : 0 62554 : 0 Query after insert 56155 : 1 20459 : 1 15365 : 1 55048 : 1 47183 : 1 49635 : 1 32939 : 1 17320 : 1 54582 : 1 62554 : 1 Query after deleting half 56155 : 0 20459 : 0 15365 : 0 55048 : 0 47183 : 0 49635 : 1 32939 : 1 17320 : 1 54582 : 1 62554 : 1 Query after deleting the rest 56155 : 0 20459 : 0 15365 : 0 55048 : 0 47183 : 0 49635 : 0 32939 : 0 17320 : 0 54582 : 0 62554 : 0
Now, I think that doing this is cheating, a little, because I'm using the symbol table, which is a hash. But, I don't think this is possible in pure Perl, not with the constraints you've placed on it.
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In reply to Re: Data structure challenge
by dragonchild
in thread Data structure challenge
by Abigail-II
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