As long as we're only talking big-O notation, I think that that O(n) initialization is a wash. Inserting n items at O(1) is O(n). And O(n) (for initialization) + O(n) (for n insertions) = O(n).

In reply to Re^4: Data structure challenge (amortized) by sleepingsquirrel
in thread Data structure challenge by Abigail-II

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