Would this be a knapsack problem? You have a grid X by Y, and want to fit blocks into that space, where, if P is the number of processors, then X' = floor(log2(P)) and Y' = P / floor(log2(P)) (there might be an off by one here...). You could also switch X' and Y' around to help "fit" them into your knapsack.

--MidLifeXis

In reply to Re: Visualisation of environment by MidLifeXis
in thread Visualisation of environment by AndreasL

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