i had a post a few days ago asking the best way to parse apache log files. i wasnt able to get apache::parselog to work so i wrote a small script using sed and awk. it produces output like so: 
[24/Mar/2004:12:26:52 /manual/misc/perf-tuning.html 0_seconds

[24/Mar/2004:12:27:33 /manual/mod/mod_status.html 0_seconds

[24/Mar/2004:12:27:39 /manual/mod/module-dict.html 0_seconds

[24/Mar/2004:12:27:46 /manual/misc/rewriteguide.html 0_seconds

[24/Mar/2004:12:27:53 /manual/mod/mod_rewrite.html 0_seconds

[24/Mar/2004:12:27:53 /manual/images/mod_rewrite_fig1.gif 0_seconds

[24/Mar/2004:12:27:53 /manual/images/mod_rewrite_fig2.gif 0_seconds

[24/Mar/2004:12:28:05 /manual/new_features_1_3.html 0_seconds

[download]
these results are sent to a file for viewing. obviously this isnt the best way to view stats for each file. is there a simple way with perl to parse the file and have the ability to pass a file name as an argument?

i know that i'd have to call the awk script each time to generate a current file which i can do.. but i dont have any ideas how to get perl involved.. is this easy or am i in over my head here?

Edit by tye, escape [

20040327 Edit by BazB: Changed title from 'how do i sort thee?'

In reply to Obtaining Apache logfile stats? by mvam

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