Anonymous Monk,
If I understand your requirements: The clearest way I can think to do this is to walk through the all the keys of the second hash for each inner key in the first hash. The only optimization I have done is return once a match is found.
#!/usr/bin/perl use strict; use warnings; my %hash1 = ( foo => { 'a' => 1, 'b' => 2, 'c' => 3 }, bar => { 'd' => 1, 'e' => 2, 'f' => 3 }, ); my %hash2 = ( blah => { 'm' => 1, 'd' => 2, 'a' => 3 }, asdf => { 'z' => 1, 'l' => 2, 'b' => 3 }, ); for my $outer_key ( keys %hash1 ) { for my $inner_key ( keys %{ $hash1{$outer_key} } ) { my ($h2_outer, $h2_inner) = Find_Key( $inner_key , \%hash2 ); if ( $h2_inner ) { # do something : $outer_key, $inner_key, $h2_outer, and $h +2_inner } else { # do your other thing } } } sub Find_Key { my ($match, $hash) = @_; for my $key ( keys %$hash ) { for ( keys %{ $hash->{$key} } ) { return ($key, $_) if $_ eq $match; } } return (undef, undef); }
If this code is not any clearer, please let me know and I will give a blow by blow explanation.

Cheers - L~R


In reply to Re: Some Explanation about inner hashes by Limbic~Region
in thread Some Explanation about inner hashes by Anonymous Monk

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