Since the values of your first hash are keys into your second hash, you don't need to do so much looping:

for my $k1 (keys %hash1) {
   my $k2 = $hash1{$k1};
   $hash1{$k1} = $hash2{$k2} if exists $hash2{$k2};
}

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duff

In reply to Re: Replace the value of a hash by duff
in thread Replace the value of a hash by Anonymous Monk

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