Suppose I have a hash whose values are anonymous functions, e.g., 
%functions = (
  '?' => 0,
  'HELLO' => sub { print "Hello, world.\n" },
  'HELP' => sub { print "Type 'hello' or 'goodbye'\n" },
  'GOODBYE' => sub { print "Goodbye...\n"; exit(0) }
);
# have to initialize this outside declaration of %functions
$functions{'?'} = $functions{'HELP'};

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Then, suppose I want to take input from the user and see if the things the user types are keys in the hash. If so, I execute the associated function. 
while(<>) {
  $func = $_;
  chomp($func);
  $func = uc($func);
  if( defined($functions{$func}) ) {
    ### insert code here to execute function in hash ###
  }
  else {
    print "\"$func\" not defined\n";
  }
}

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My question is this. At the spot to insert the code to execute the function, I would like to do this: 
    &$functions{$func};

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but perl won't let me. I have found that if I do this: 
    my $code;
    $code = $functions{$func};
    &$code;

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it works. Why doesn't the first work?

In reply to using a hash of functions by Anonymous Monk

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