Your solution seems flawed to me: consider
my $ha = [ [1,2], [5,5,5], [1,2], [3,4] ];
my $hb = [ [4,3], [1,2], [2,1,5], [5,5] ];

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These are clearly different, but your code still outputs "same" since it is discarding the entire original structure (and not only the order of elements).

In reply to Re: Re: Comparing unordered hierarchical arrays by ant9000
in thread Comparing unordered hierarchical arrays by kvale

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