Hi Monks;
I am having a problem trying to format a url. The last part of my url will be names with spaces between them. Example, if the last name of my url looks like something like:
Inn House Company and Services, my url will end like this "http://my.test.com?infor=info2&company_name=Inn" everything after the first word because is followed by space will not be part of the url. What I am trying to do is to replace all the spaces coming from a variable $company_name per example, that has spaces in it to %20, but some how I am still not able to make one that would take any name format.
I am wondering is there is a better way to say:
I any company name has any spaces between them replace the spaces with %20, here is my regular expression, but as you can see it is not efficient as it should be.
if ($company_name=~s/(\w\&\w|\w*)(\s?)(\w*)(\s?)(\w*|\w\.)(\s?)(.*)$/$
+1%20$3%20$5%20$7/)
.....

[download]

And I do have names like:
Soft, Inc. LTD
Y.O.U Co. and Services
General Help Company

It can also make the reg. exp. even more difficulty to match.
Thanks for the help.

20040409 Edit by BazB: Changed title from 'Regular Expression'

In reply to Encoding a URL with regular expressions? by Anonymous Monk

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