I have no idea what you're really asking, but when you do "use module;" that module will only export it's functions to the callers namespace. So the functions from that module will only be available, in the unqualified form, to whichever package directly uses that module. Note you can still access any function you want via the "Package::Function()" syntax.

In reply to Re: A question of module scope by BUU
in thread A question of module scope by jcpunk

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