P6R is fun, but a little maddening, too. I see that I am going to have to learn Perl 6 more! Anyway, I am stumped why $0 doesn't contain three hash keys in the code below. The input looks like this: 
hEAD: one

DeCK: two

By: three

four I<five six>

BiO: seven

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Shouldn't $0 have hash keys foo and deck? 
use strict;
use Perl6::Rules -debug;

rule head    :i { HEAD <COLON> }
rule deck    :i { DECK <COLON> }
rule byline :i { BY <COLON> }
rule bio     :i { BIO <COLON> }
rule body     :w { <para> [<blankline> <para>]* }
rule para     :w { <line>+ }
rule figure :i { }
rule line     { <word>+? \v }
rule word    { <italics> | <[\S+]>? }
rule italics :w { I <LANGLE> ([<word>|\v]+) <RANGLE> }
rule blankline    { ^^$$ }
rule COLON            { \: }

"abcd" =~ m/a  $?foo:=(..)  d/;
print "yes" if ($0->{foo} eq "bc");
$0->dump();

#
# get all input
my @line = <>; my $line = join('', @line);

if ($line =~
    m:words/
        <head> $?foo:=(<line>)
        <deck> $?deck:=(<line>)    
        [<byline> $?by:=(<line>)]?    
    /)
{
    $0->dump();
}

[download]

In reply to Perl6::Rules oddity? by supergiantrobot

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